The Poisson distribution and Stirling numbers

September 16, 2008

While working on an assignment for my machine learning class, I rediscovered the fact that if X is a random variable from a Poisson distribution with parameter \lambda, then

\displaystyle E[X^n] = \sum_{k=1}^n S(n,k) \lambda^k,

where S(n,k) denotes a Stirling number of the second kind. (I actually prefer Knuth’s curly bracket notation, but I can’t seem to get it to work on this blog.) In particular, if \lambda = 1, then E[X^n] is the nth Bell number B_n, the number of ways of partitioning a set of size n into subsets!

As it turned out, this didn’t help me at all with my assignment, I just thought it was nifty.


First day of class

September 4, 2008

I’ve been waiting for this day for four years now. It didn’t disappoint. This is shaping up to be a fun semester!